-(y+3+2xy+y^2)=0

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Solution for -(y+3+2xy+y^2)=0 equation:


Simplifying
-1(y + 3 + 2xy + y2) = 0

Reorder the terms:
-1(3 + 2xy + y + y2) = 0
(3 * -1 + 2xy * -1 + y * -1 + y2 * -1) = 0
(-3 + -2xy + -1y + -1y2) = 0

Solving
-3 + -2xy + -1y + -1y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + -2xy + -1y + 3 + -1y2 = 0 + 3

Reorder the terms:
-3 + 3 + -2xy + -1y + -1y2 = 0 + 3

Combine like terms: -3 + 3 = 0
0 + -2xy + -1y + -1y2 = 0 + 3
-2xy + -1y + -1y2 = 0 + 3

Combine like terms: 0 + 3 = 3
-2xy + -1y + -1y2 = 3

Add 'y' to each side of the equation.
-2xy + -1y + y + -1y2 = 3 + y

Combine like terms: -1y + y = 0
-2xy + 0 + -1y2 = 3 + y
-2xy + -1y2 = 3 + y

Add 'y2' to each side of the equation.
-2xy + -1y2 + y2 = 3 + y + y2

Combine like terms: -1y2 + y2 = 0
-2xy + 0 = 3 + y + y2
-2xy = 3 + y + y2

Divide each side by '-2y'.
x = -1.5y-1 + -0.5 + -0.5y

Simplifying
x = -1.5y-1 + -0.5 + -0.5y

Reorder the terms:
x = -0.5 + -1.5y-1 + -0.5y

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